# Write a program that asks the user to enter the month (letting the user enter an integer in the…

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Write a program that asks the user to enter the month (letting the user enter an integer in the range of 1 through 12) and the year. The program should then display the number of days in that month. Use the following criteria to identify eap years: 1. Determine whether the year is divisible by 100. If it is, then it is a leap year if and only if it is divisible by 400. For example, 2000 is a leap year but 2100 is not CDI 2. If the year is not divisible by 100, then it is a leap year if and if only it is divisible by 4. For example, 2008 is a leap year but 2009 is not. Here is a sample run of the program: Enter a month (1-12): 2 [ Enter] Enter a year: 2008 [Enterl 29 days

Program:

#include <iostream>

using namespace std;

int main()
{
int month, year;
cout<<“Enter a month (1 – 12):”;
cin>>month;

cout<<“n”;

cout<<“Enter a year:”;
cin>>year;

cout<<“n”;

//check if the entered month is February i.e month = 2
if(month == 2)
{
//Check if the entered year is a leap year or not
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
{
cout<<“29 days”; // if it is a leap year, then print 29 days in month 2
}
else
{
cout<<“28 days”; //if it is not a leap year, the print 28 days in month 2
}
}
//check for rest of the months
else if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month ==12)
{
cout<<“31 days”;
}
else
{
cout<<“30 days”;

}

return 0;
}

Output:

Enter a month (1 – 12) :2 Enter 29 days a year:2008 .Program finished with exit code 0 Press ENTER to exit console

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