# Question: Write a recursive method that counts the number of mines on a grid. A mine is defined as a contig……

Write a recursive method that counts the number of mines on a grid. A mine is defined as a contiguous collection of X’s (connected horizontally and vertically). In java language

Input

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Max dimensions of the array

Distribution of mines on the array

Output

The number of mines and the layout of the grid showing the locations of the mines.

Requirements checklist:

❑ Documented source code (include any assumptions you make)

Input File (in.txt)

The format of the input file is as follows: First line is the dimensions of the grid.. Then the grid containing 1s for the creatures and 0s for the spaces. The file terminates by 0 0.

5 5

…..

.XXX.

…..

…..

…..

5 5

….X

.XXX.

X….

…..

…..

0 0

Output File (out.txt)

Experiment # 1

Number of Mines: 1

0 0 0 0 0

0 1 1 1 0

0 0 0 0 0

0 0 0 0 0

0 0 0 0 0

Experiment #2

Number of Mines: 3

0 0 0 0 1

0 2 2 2 0

3 0 0 0 0

0 0 0 0 0

0 0 0 0 0

Marking Scheme

Out of

Documentation

3

Meaningful variable names

2

Correct input format

2

Correct output format

2

Modularity

4

Tested

12

Total

25

import java.io.File;

import java.io.FileNotFoundException;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

public class Mine {

public static void main(String[] args) throws IOException {

File file =

new File(“D:\mine.txt”);

Scanner sc = null;

//For writing

FileWriter writer =null;

try {

//To scan the file

writer = new FileWriter(“D:\out.txt”, true);

sc = new Scanner(file);

} catch (Exception e) {

e.printStackTrace();

}

int l=0;

while(sc.hasNextLine()){

l++;

int m=0;

String[] data=sc.nextLine().split(” “);

int row=Integer.parseInt(data[0]);

int col=Integer.parseInt(data[1]);

int [][] result=new int[row][col];

int i=0,j=0;

while(i<row){

j=0;

boolean flag=true;

String line=sc.nextLine();

while(j<col){

char value=line.charAt(j);

if(value==’X’){

if(flag){

m++;

flag=false;

}

result[i][j]=m;

}else{

result[i][j]=0;

}

j++;

}

i++;

}

//writing in out.txt if row > 0

if(row!=0){

writer.write(“Experiment # “+l);

writer.write(“rn”);

writer.write(“Number of Mines:”+m);

writer.write(“rn”);

for(int temp[]:result){

for(int temp1:temp){

writer.write(temp1+” “);

}

writer.write(“rn”);

}

}

}

writer.close();

}

}

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