2) lets take 100 g of the sample
Cu = 25.45 g = 25.45 g/ 63.546 g/mol = 0.4 mol
S = 12.84 g = 12.84 g / 32 g/mol = 0.4 mol
H = 4.036 g = 4.036 mol
O = 57.67 g = 57.67 g / 16 g/mol = 3.6 mol
The smallest number of moles is 0.4 and by dividing the individual moles with 0.4 we get the empirical formula
3) C = 0.7238g / 12g/mol = 0.06 mol
H = 0.07088 g/ 1 g/mol = 0.07088 mol
N = 0.1407 g / 14 g/mol = 0.01 mol
O = 0.3214 g / 16 g/mol = 0.02 mol
Dividing the individual moles with the smallest one 0.01gives the empirical formula
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