Question: 1) Complete the following code fragment: System.out.print ("Enter time in seconds: ") secondskb.n……

1) Complete the following code fragment: System.out.print (“Enter time in seconds: “) secondskb.nextInt () /* Write nested if else to convert seconds into hours and minutes as follows: There are 3,600 seconds in an hour. If the number of seconds entered by the user is greater than or equal to 3, 600, the program should display the number of hours, minutes, and leftover seconds in that many seconds There are 60 seconds in a minute. If the number of seconds entered by the user is greater than or equal to 60, the program should display the number of minutes and leftover seconds in that many seconds. */ Write a method named findFactors which takes three parameters of type int: start, finish, and num. Use a while loop to count the numbers in the range start to finish (inclusive) which are divisible by num. The method returns the count using return type of int. Declare any additional variables that you use. The outline of the method is given below:(Hint: Use % operator.) 2) public int findFactors (int start, int finish, int num) int count 0; return count

I am making findFactors static so that I can call in the same class.

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Question: 1) Complete the following code fragment: System.out.print ("Enter time in seconds: ") secondskb.n……
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1)code snippet:-

****************************************

System.out.print(“Enter time in seconds:”);

Scanner kb=new Scanner(System.in);

int seconds=kb.nextInt();

int hrs=0;

int mins=0;

if(seconds>=3600){

hrs=seconds/3600;

mins=(seconds%3600)/60;

seconds=seconds%60;

System.out.print(hrs+” hrs ” +mins +” min ” + seconds+ ” secn”);

}

else if(seconds>=60){

mins=(seconds)/60;

seconds=seconds%60;

System.out.print(mins +” min ” + seconds+ ” secn”);

}else{

System.out.print( seconds+ ” secn”);

}

********************************************************

2)Code snippet:-

********************************************************

int count=0;

for (int i=start;i<=finish;i++){

if(num%i==0){

count++;

}

}

return count;

}

***********************************************************

code used for testing :-

import java.util.Scanner;

class Sec{

public static void main(String args[]){

System.out.print(“Enter time in seconds:”);

Scanner kb=new Scanner(System.in);

int seconds=kb.nextInt();

int hrs=0;

int mins=0;

if(seconds>=3600){

hrs=seconds/3600;

mins=(seconds%3600)/60;

seconds=seconds%60;

System.out.print(hrs+” hrs ” +mins +” min ” + seconds+ ” secn”);

}

else if(seconds>=60){

mins=(seconds)/60;

seconds=seconds%60;

System.out.print(mins +” min ” + seconds+ ” secn”);

}else{

System.out.print( seconds+ ” secn”);

}

System.out.print( findFactors(1,10, 50));

}

public static int findFactors(int start,int finish, int num){

int count=0;

for (int i=start;i<=finish;i++){

if(num%i==0){

count++;

}

}

return count;

}

Remember my second output is test for the method.

}

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