# Q43. private int func2(int m, int n) {       if (n == 0)             return 0;       else             return m + func2(m, n-1);…

 Q43. private int func2(int m, int n) { if (n == 0) return 0; else return m + func2(m, n-1); } Which of the following statements about the code above is always true? a. func2(m,n) = func2(n, m) for m >= 0 b. func2(m,n) = m * n for n >=0 c. func2(m,n) = m + n for n >=0 d. func2(m, n) = n * m for n >=0 Don't use plagiarized sources. Get Your Custom Essay on Q43. private int func2(int m, int n) {       if (n == 0)             return 0;       else             return m + func2(m, n-1);… Get an essay WRITTEN FOR YOU, Plagiarism free, and by an EXPERT! Q44. A method is called directly recursive if it calls another recursive method. a. true b. false Q45. Recursion starts with the base case. a. true b. false Q46. public static int exampleRecursion (int n) { if (n==0) return 0; else return exampleRecursion(n-1) + n*n*n; } Refer to the code above. What is the output of exampleRecursion(0)? a. 0 b. 3 c. 9 d. 27 Q47. In the base case, the solution is obtained through a call to a smaller version of the original method. a. true b. false Q48. In reality, if you execute an infinite recursive method on a computer it will execute forever. a. true b. false Q49. Every recursion definition must have zero or more base cases. a. true b. false Q50. private int func1(int m, int n) { if (m==n || n==1) return 1; else return func1(m-1,n-1) + n*func1(m-1,n); } What precondition must exist in order to prevent the code above from infinite recursion? a. m > = 0 and n >= 0 b. m >= 0 and n >= 1 c. m >= 1 and n >= 0 d. m >= 1 and n >= 1

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